The one idea
Photons do not deposit dose. They hand energy to electrons, and the electrons deposit it somewhere else. Every dose quantity in this module is a way of keeping track of where that energy was handed over and where it finally stayed.
Module 03 followed photons through attenuation and showed that μtr and μen track how much of each interaction's energy goes to electrons. This module takes the next step. Multiply the energy fluence by μtr/ρ and you get kerma. Ask when kerma equals dose and you get charged particle equilibrium. Put a small air cavity in the medium and ask what dose the air receives and you get cavity theory, which is how every ion chamber calibration works.
Three answers carry the whole module:
- Under charged particle equilibrium, absorbed dose equals collision kerma. That lets you calculate dose from the photon beam alone.
- One coulomb of ionization in air corresponds to 33.97 joules deposited. That number, W/e, converts charge to dose in air.
- A small cavity converts with stopping power ratios; a large one with μen ratios. The size is judged against the range of the electrons, not against the patient.
When a dose quantity confuses you, ask two questions: whose energy is being counted (photon or electron), and where is it being counted (at the interaction or where it is absorbed). Every definition in this module answers those two questions differently.
Counting the beam: fluence
Before you can say how much energy a beam deposits, you need a way to say how much beam there is at a point. Picture a small sphere centred on the point. Count the photons that cross it, from any direction, and divide by the sphere's cross-sectional area. That is the particle fluence, Φ, in photons per square metre (usually quoted per cm²). Using a sphere rather than a flat plate means a photon counts once whatever direction it travels, which matters inside a patient where scattered photons come from everywhere.
Weight each photon by its energy and you have the energy fluence, Ψ, in joules per square metre. For a single photon energy the two are related simply. For a real beam you sum over the spectrum. The rates, fluence per unit time, are the fluence rate and energy fluence rate.
Worked number: 1.0 × 1010 photons/cm² of 1.25 MeV carry Ψ = 1.0 × 1010 × 1.25 MeV × 1.602 × 10−13 J/MeV = 2.0 × 10−3 J/cm².
Fluence is a property of the radiation field at a point. It is not a dose and has no medium attached. Kerma and dose need a medium, because they depend on what the photons interact with.
Kerma: energy handed over
When a photon interacts, some of its energy becomes kinetic energy of electrons (the Compton electron, the photoelectron, the electron and positron from pair production). The rest leaves as a scattered photon, a characteristic x-ray, or annihilation radiation. Kerma (kinetic energy released per unit mass) counts only the kinetic energy given to charged particles in a small mass, at the place where the photon interacted. Its unit is the gray, J/kg, the same as dose.
Kerma has the shape it has because it is the product of how much energy passes the point (Ψ) and what fraction of that energy is transferred to electrons per unit mass of the medium (μtr/ρ). More photons, or a medium that takes a bigger share of each photon's energy, means more kerma.
Worked number: continuing from section 02, Ψ = 2.0 × 10−3 J/cm² of 1.25 MeV photons in water, μen/ρ = 0.0296 cm²/g. Kcol = 2.0 × 10−3 × 0.0296 = 5.9 × 10−5 J/g = 0.059 J/kg = 5.9 cGy.
| Increase this | Effect on kerma | Why |
|---|---|---|
| Energy fluence | Rises in proportion | More energy crossing the point |
| Distance from a point source (in air) | Falls as 1/r² | Fluence spreads over a larger area |
| Depth in a medium | Falls, roughly exponentially | Primary photons are attenuated; kerma is greatest at the surface |
| Z of medium at kV energies | Rises steeply | Photoelectric μen/ρ scales roughly with Z³ |
| Electron energy (radiative fraction g) | Kcol/K falls slightly | Faster electrons in higher-Z media lose more to bremsstrahlung |
Kerma is defined only for indirectly ionizing radiation (photons and neutrons). It is maximal at the surface of a phantom and falls with depth from the first millimetre. Radiative fraction g is small in tissue: about 0.3 percent for Co-60 photons in air, rising with energy and with Z.
Absorbed dose: energy that stays
Kerma tells you where electrons were launched. Absorbed dose tells you where their energy ended up. It is the mean energy imparted by all ionizing radiation to a small mass, divided by that mass. Energy imparted is everything that comes in (photons and electrons) minus everything that goes out, so electrons launched upstream that stop inside the mass count, and electrons launched inside that leave do not.
Dose applies to any ionizing radiation, directly or indirectly ionizing, in any medium. It is what biology responds to and what you prescribe.
| Quantity | What it counts | Radiation | Unit |
|---|---|---|---|
| Fluence Φ, Ψ | Photons (or energy) crossing a small sphere | Any | m⁻², J/m² |
| Kerma K | Kinetic energy given to charged particles, at the interaction site | Photons, neutrons | Gy |
| Collision kerma Kcol | The part of K not later radiated as bremsstrahlung | Photons, neutrons | Gy |
| Exposure X | Charge of one sign produced in air by the electrons a photon beam sets moving | Photons, in air only | C/kg, R |
| Absorbed dose D | Energy imparted that stays in the mass | Any | Gy |
| Equivalent dose HT | Organ dose × radiation weighting factor wR (protection only) | Any | Sv |
For protection, ICRP 103 assigns wR = 1 for photons and electrons, 2 for protons, 20 for alpha particles, and an energy-dependent value for neutrons. Effective dose then weights organs by tissue factors. These are risk quantities for populations and belong to Module 21; never use them for a patient's treatment dose.
Treating kerma and dose as interchangeable because they share a unit. At the skin of a megavoltage patient, kerma is at its maximum and dose is a fraction of its peak. They are equal only under the conditions in the next section.
Charged particle equilibrium
Take a small volume in a uniform photon beam. Electrons are launched inside it and some carry energy out. Electrons launched upstream carry energy in. If, for every electron that leaves with some energy, another of the same energy enters, the volume keeps exactly the energy that was transferred inside it, minus the bremsstrahlung that escapes. That balance is charged particle equilibrium (CPE), and under it:
CPE needs the photon fluence to be uniform over a region at least as large as the maximum electron range around the point, in a uniform medium. In a real megavoltage beam that is never quite true, because the photons are attenuated over the distance the electrons travel. The electrons arriving at a point were launched upstream, where the photon fluence was slightly higher. So beyond the buildup region, dose is a little larger than the local collision kerma, by a nearly constant factor β. Physicists call this transient charged particle equilibrium (TCPE).
| Region (MV beam in water) | Relation | Why |
|---|---|---|
| Surface and buildup, 0 to dmax | D < Kcol | Not enough upstream electrons yet; more energy leaves than enters |
| At dmax | D ≈ Kcol | The curves cross; this is the closest a real beam gets to CPE |
| Beyond dmax | D = β Kcol, β > 1 | Electrons carry energy from upstream, where fluence was higher |
| Ideal, no attenuation | D = Kcol | True CPE; approached for Co-60 more closely than for 18 MV |
Kerma and dose through the buildup
Teaching model, not commissioning dataThe amber curve is primary collision kerma, highest at the surface. The blue curve is dose, built from electrons launched upstream. Watch where they cross, then watch the gap beyond the crossing grow from Co-60 to 18 MV. Tick the box and the gap disappears.
Model: Kcol = 100·e−μd for primary photons with μ fixed by a representative energy (1.25, 2 and 6 MeV); dose is that kerma carried forward by electrons with an exponential range kernel, which gives D = β·Kcol(1 − e−(λ−μ)d) with β = λ/(λ − μ). λ is chosen so the crossing sits at a typical dmax. Scatter and contaminant electrons are left out, so the model starts at zero surface dose; real 6 MV beams start at roughly 15 to 25 percent.
CPE fails, and D cannot be computed as Kcol, in the buildup region, near interfaces between different media, at field edges (penumbra), in small fields and in low-density lung where electron ranges grow, close to brachytherapy sources, and at high energy. Exposure and kerma-based calibrations need CPE, which is why exposure is not used above about 3 MeV.
Lung SBRT with a small field: electrons travel three to five times farther in lung, more leave the beam than return, and dose on axis falls below what a kerma-based algorithm predicts. This is lateral electronic disequilibrium, the reason type B algorithms or Monte Carlo are required in lung (Module 08, section 07).
Exposure, W/e and the f-factor
Before anyone could measure energy deposited directly, they could measure charge. Exposure, X, is the total charge of one sign produced in a small mass of air when all the electrons liberated by photons in that mass are stopped completely in air. It is the ionization equivalent of collision kerma in air. Its SI unit is C/kg; the old unit, the roentgen, is 1 R = 2.58 × 10−4 C/kg.
To turn charge into energy you need the average energy spent per ion pair formed in dry air, W. Divided by the electron charge, W/e = 33.97 J/C (equivalently 33.97 eV per ion pair). ICRU Report 90 kept this value and widened its uncertainty to about 0.35 percent. Multiply exposure by W/e and you have collision kerma in air.
To get dose in another medium placed at the same point, under CPE, scale by how much more energy per gram that medium absorbs from the same photon fluence: the ratio of mass energy absorption coefficients. The combination is the f-factor, in cGy per R.
| Medium | f at kV (≈ 30 keV) | f at Co-60 and MV | Why |
|---|---|---|---|
| Water, muscle | ≈ 0.9 | ≈ 0.97 | Hydrogen gives water more electrons per gram than air |
| Fat | lower than muscle | ≈ 0.97 | Low Z; more hydrogen |
| Cortical bone | several times muscle (≈ 4×) | ≈ 0.92 | Photoelectric Z³ dependence at kV; fewer electrons per gram at MV |
Approximate values after Khan and Gibbons and Attix. Bone figures depend on the composition assumed. Learn the direction and the rough size: bone much higher at kV, slightly lower than soft tissue at megavoltage.
Exposure is defined only for photons, only in air, and is practical only up to about 3 MeV, because above that the secondary electrons travel too far for an ionization chamber to achieve CPE. It cannot be used for electron beams. Modern calibration (TG-51) bypasses exposure and calibrates chambers directly in dose to water.
Bragg-Gray cavity theory
An ion chamber measures dose to the air in its cavity. You want dose to the water around it. Cavity theory connects the two.
Suppose the cavity is so small that photons essentially never interact in it. Every bit of dose in the air then comes from electrons launched in the surrounding water that cross the cavity. If the cavity is also too small to change the number or energy of those electrons, the same electron fluence crosses the air as would have crossed the water it replaced. Dose from an electron fluence is fluence times mass collision stopping power, energy lost per unit path per unit density. The ratio of doses is therefore the ratio of stopping powers.
The two Bragg-Gray conditions are worth stating exactly, because exams ask for them:
- The cavity does not perturb the charged particle fluence in the medium (it is small compared with electron ranges).
- The dose in the cavity is deposited entirely by charged particles crossing it; photon interactions in the cavity itself are negligible.
CPE is not one of the conditions. Bragg-Gray works in regions without CPE, which is why it holds for electron beams and why chambers work at depth in megavoltage beams.
Worked number: a cavity collects charge that gives Dair = 0.959 Gy in a Co-60 beam. With s̄water,air = 1.133, Dwater = 0.959 × 1.133 ≈ 1.09 Gy, before perturbation corrections.
| Beam | s̄water,air (approx.) | Comment |
|---|---|---|
| Co-60 | ≈ 1.13 | The reference beam for chamber calibration coefficients |
| 6 MV | ≈ 1.12 | Falls slowly as photon energy rises |
| 18 MV | ≈ 1.10 | Higher-energy electrons; density effect in water |
| Electron beams | ≈ 0.97 to 1.10 | Varies strongly with depth and energy, so TG-51 handles it at a reference depth |
Spencer-Attix values, rounded. The exact numbers sit inside the kQ factors your physicist uses; they are given here for direction and size, not for calculation.
Converting an ion chamber's air dose with the μen ratio (≈ 1.11) instead of the stopping power ratio (≈ 1.13). An air cavity a few millimetres across is small compared with megavoltage electron ranges, so it is a Bragg-Gray cavity. The wrong ratio understates water dose by about 2 percent.
Spencer-Attix and large cavities
Spencer-Attix: the delta-ray fix
Bragg-Gray treats every electron as losing energy continuously along its track. Real electrons occasionally knock out a fast secondary electron, a delta ray, that may itself cross the cavity or escape it. Spencer and Attix split electrons at a cutoff energy Δ, the energy an electron needs to just cross the cavity (about 10 keV for a typical chamber). Energy losses that create electrons below Δ are counted as local; electrons above Δ are counted as part of the fluence. The ratio uses restricted stopping powers, LΔ/ρ, plus a track-end term for electrons that fall below Δ.
Large cavities: back to μen
Now make the detector large compared with electron ranges, for example a thick LiF chip in a kilovoltage beam, or any detector thick enough to set up its own CPE. Electrons from the surrounding medium deposit their energy in a thin rim; almost all the dose in the detector comes from photons interacting in the detector material itself. Under CPE in both media, each dose is Kcol = Ψ·μen/ρ, and the photon fluence is common, so the ratio is the μen ratio.
| Detector size vs electron range | Dose comes from | Conversion | Example |
|---|---|---|---|
| Small | Electrons from the medium crossing it | Stopping power ratio | Air-filled ion chamber in MV photons or electrons |
| Intermediate | Both | Burlin weighting | TLD chip in Co-60; diode in MV beams |
| Large | Photons interacting in the detector | μen ratio | Thick TLD or dosimeter in a kV beam |
"Small" and "large" are relative to the range of the secondary electrons, so the same detector can be a small cavity at 18 MV and a large one at 50 kV. Energy dependence of a detector is largest when its effective Z differs from water and the beam is kilovoltage, where μen ratios swing with photoelectric absorption.
Small cavity, stopping powers. Large cavity, μen. CPE needed for large cavities, not for Bragg-Gray.
Cavity bench
Follow one chamber reading all the way to dose to water. Change the room temperature and pressure and watch the air mass, and therefore the dose, move. Then compare the Bragg-Gray answer with what you would get from the wrong (μen) ratio.
Charge to dose to water
Teaching model, not a calibration0.6 cm³ is a Farmer chamber; 0.01 to 0.1 cm³ is a small-volume or micro chamber. Dry air density at 20 °C and 101.325 kPa is taken as 1.2045 kg/m³ and scaled by the ideal gas law.
The temperature-pressure correction you see on every output check, PTP, is this same air-mass effect. A vented chamber on a hot, low-pressure day contains less air, collects less charge, and would under-read by a percent or more if the correction were skipped.
Worked examples
Work each one on paper first. The constants are given in the problem, as they are on the exam.
Exposure to air kerma to water dose
A Co-60 beam delivers an exposure of 100 R at a point in air. W/e = 33.97 J/C, 1 R = 2.58 × 10−4 C/kg, and (μen/ρ)water/(μen/ρ)air = 1.112. Find the air collision kerma and the dose to a small mass of water at that point, just large enough for CPE.
Show solution
87.6 cGy in air; ≈ 97 cGy to water
Sanity check: water absorbs about 11 percent more per gram than air at megavoltage, so the water dose must be a little higher than the air kerma and a little below 100 cGy. The common wrong answer is "100 R = 100 cGy", which ignores both W/e and the medium.
Fluence to kerma to dose
A point in water receives a fluence of 1.0 × 1010 photons/cm² of 1.25 MeV. (μen/ρ)water = 0.0296 cm²/g and the radiative fraction g = 0.003. 1 MeV = 1.602 × 10−13 J. Find the collision kerma, the total kerma, and the dose under CPE.
Show solution
Energy fluence: Ψ = 1.0 × 1010 × 1.25 × 1.602 × 10−13 = 2.0025 × 10−3 J/cm².
Kcol ≈ 5.93 cGy, K ≈ 5.95 cGy, D ≈ 5.93 cGy
Sanity check: the units chain J/cm² × cm²/g gives J/g; multiply by 1000 for J/kg (Gy). Forgetting that factor gives 0.0059 cGy. Dose equals collision kerma, not total kerma; in water at Co-60 the difference is tiny, which is why it is a recall question more than a calculation one.
Chamber charge to air dose
A 0.600 cm³ vented chamber collects 20.0 nC at 22 °C and 100.0 kPa. Dry air density is 1.2045 kg/m³ at 20 °C and 101.325 kPa. W/e = 33.97 J/C. Find the mean dose to the air in the cavity.
Show solution
Air density at room conditions: ρ = 1.2045 × (293.15/295.15) × (100.0/101.325) = 1.181 kg/m³. Mass: m = 1.181 × 0.600 × 10−6 m³ = 7.08 × 10−7 kg (0.708 mg).
≈ 0.96 Gy to air
Sanity check: a Farmer chamber collects roughly 20 nC per Gy, so tens of nanocoulombs means about a gray. Using the reference density without correcting for 22 °C and 100 kPa gives 0.940 Gy, 2 percent low; that 2 percent is the PTP correction.
Bragg-Gray to dose to water
The chamber in EX 3 sat at depth in water in a Co-60 beam. Take s̄water,air = 1.133 and (μen/ρ)water,air = 1.112, and ignore perturbation corrections. What is the dose to water? What would you get with the wrong ratio?
Show solution
An air cavity a few millimetres across is small compared with Co-60 electron ranges in water, so it is a Bragg-Gray cavity and the stopping power ratio applies.
≈ 1.09 Gy to water
Sanity check: water dose is above air dose by about 13 percent, because water has more electrons per gram than air and stops electrons faster. Dividing instead of multiplying gives 0.846 Gy, an answer below the air dose, which cannot be right.
Bone at kilovoltage and megavoltage
A soft-tissue point receives 2.00 Gy. A small piece of cortical bone at the same location sees the same photon fluence, and CPE holds in both. The ratio (μen/ρ)bone/(μen/ρ)tissue is about 4.0 for a beam with effective energy 30 keV and about 0.96 at 1.25 MeV. Find the bone dose in each beam.
Show solution
8.0 Gy at kV; ≈ 1.9 Gy at Co-60
Sanity check: at kV the photoelectric effect (Z³) makes calcium-rich bone a strong absorber; at megavoltage, Compton dominates and bone has slightly fewer electrons per gram than soft tissue, so its dose per gram is slightly lower. Thin soft tissue inside bone, such as marrow and osteocytes, is an intermediate cavity and receives less than the bulk bone figure.
In the planning room
You will never compute a Spencer-Attix ratio in clinic. You will hear these ideas every time a plan is reported in dose to medium, a detector is chosen for skin dose, or a chamber reading is turned into a calibration.
Ballpark numbers to carry in your head
| Quantity | Rough number | What it tells you |
|---|---|---|
| W/e in dry air | 33.97 J/C | Charge to energy; the anchor of every ion chamber |
| Air kerma per roentgen | 0.876 cGy/R | Exposure to air collision kerma |
| f-factor, water, MV | ≈ 0.97 cGy/R | Water absorbs about 11 percent more than air |
| s̄water,air, Co-60 | ≈ 1.13 | Air dose to water dose in a chamber |
| Farmer chamber sensitivity | ≈ 20 nC/Gy | 0.6 cm³ of air; small chambers collect proportionally less |
| Dose to water versus dose to medium in cortical bone, MV | ≈ 10% higher Dw | Ratio of water to bone stopping powers; small in soft tissue |
Dose to water or dose to medium
Monte Carlo and grid-based Boltzmann solvers (Acuros XB) compute dose in the actual tissue, Dm. Convolution algorithms and every clinical trial before them report dose to water, Dw. Converting one to the other is a cavity theory problem: a small water cavity in bone is Bragg-Gray, so Dw = Dm × s̄w,m. In soft tissue the difference is about 1 to 2 percent; in cortical bone it is around 10 percent. A spine SBRT plan or a mandible constraint can therefore look different with no change in the delivered beam, only in what is being reported.
Detectors where CPE fails
Skin and buildup-region dose cannot be measured with a detector that needs CPE. Extrapolation chambers and thin-window parallel-plate chambers are the reference tools; OSLDs, TLDs and diodes used in vivo need either buildup caps, which measure dose at dmax rather than at the skin, or calibration under the same conditions as the measurement.
| Say this to physics or dosimetry | Why it lands |
|---|---|
| "Is this plan reported as dose to water or dose to medium?" | Explains a 5 to 10 percent change in bone or in a prosthesis region between algorithms |
| "How was the skin dose measured, and with what buildup?" | Shows you know a capped diode reports dmax dose, not surface dose |
| "Is the calc point in a region with electronic equilibrium?" | Points at buildup, interfaces, penumbra and small fields in lung, where kerma-based checks disagree |
| "Was PTP applied on this output check?" | Ties a percent-level output drift to air density in a vented chamber |
| "Which detector did we use for these small fields?" | Detector size versus electron range decides whether volume averaging and fluence perturbation matter (Module 17) |
Postmastectomy chest wall with bolus: the bolus supplies the upstream electrons so that the skin sits beyond the buildup, where dose approaches the kerma-limited value. Without bolus, the skin is in the region where D is far below Kcol. That is skin sparing, explained as a CPE problem.
Board pearls and traps
Indirectly ionizing radiation only. Highest at the surface.
Any radiation, any medium. 1 Gy = 1 J/kg = 100 rad.
Kcol = K(1 − g).
Not total kerma. TCPE beyond dmax: D = β·Kcol, β slightly above 1.
Curves cross near dmax; beyond it D > Kcol.
1 R = 2.58 × 10−4 C/kg.
1 R gives 0.876 cGy air kerma.
Water ≈ 0.97 cGy/R at MV. Bone ≫ tissue at kV, slightly below at MV.
Cavity small, does not perturb fluence, no photon interactions in it. CPE not required.
Cutoff Δ ≈ 10 keV accounts for delta rays.
Needs CPE in the detector. Burlin interpolates between the two.
Falls slowly with energy.
- Setting dose equal to total kerma under CPE. It equals collision kerma.
- Saying kerma peaks at dmax. Kerma peaks at the surface; dose peaks at dmax.
- Listing CPE as a Bragg-Gray condition.
- Using the μen ratio for an air-filled ion chamber in a megavoltage beam.
- Applying exposure to electron beams or to photons above about 3 MeV.
- Forgetting that "small" and "large" cavity are judged against electron range, so they change with beam energy.
- Dividing by the stopping power ratio when going from air to water. Water dose is higher.
Question bank
Exam-style single best answer. Pick one to see the explanation.
Formula card and sources
Sources
- American Board of Radiology. Study Guide for Medical Physics for Radiation Oncology (2023 domain ranges; domain II.A, radiation quantities and units).
- Attix FH. Introduction to Radiological Physics and Radiation Dosimetry. Wiley, 1986. Chapters on kerma, CPE and cavity theory.
- Khan FM, Gibbons JP. The Physics of Radiation Therapy, 5th ed. Chapters on measurement of ionizing radiation and quantification of absorbed dose.
- Podgorsak EB, ed. Radiation Oncology Physics: A Handbook for Teachers and Students. IAEA, 2005. Chapters 1 to 3.
- ICRU Report 85. Fundamental Quantities and Units for Ionizing Radiation. J ICRU 2011;11(1).
- ICRU Report 90. Key Data for Ionizing-Radiation Dosimetry: Measurement Standards and Applications. J ICRU 2014;14(1). Wair = 33.97 eV, uncertainty 0.35%.
- Almond PR et al. AAPM TG-51 protocol for clinical reference dosimetry of high-energy photon and electron beams. Med Phys 1999;26:1847.
- IAEA Technical Reports Series 398. Absorbed Dose Determination in External Beam Radiotherapy. Vienna, 2000.
- ICRP Publication 103. The 2007 Recommendations of the International Commission on Radiological Protection. Ann ICRP 2007;37.
The buildup panel uses a two-exponential teaching model and the cavity bench applies bare Bragg-Gray without perturbation factors. Both teach direction and magnitude. Clinical numbers come from your physicist's calibration and your machine's commissioning data.